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Introduction to battery-management systems- COURSERA WEEK 04 FINAL QUIZ

 Introduction to battery-management systems- COURSERA WEEK 04  FINAL QUIZ 1 . Question 1 W hich of the followi ng detection mechanisms could protect a battery pack from overcurre nt? Select all that apply. 1 point Contactor Thermal fuse Electronic protection Resettable fuse 2 . Question 2 Suppose that a small passenger vehicle expends energy at a rate of 220Wh/mile while driving. If this vehicle's battery pack is charged at a 6.6kW rate, what is the rate of range added to the battery in "miles (of range) per hour"? Round your answer to the nearest "mph". 1 point 3 . Question 3 Suppose that a positive-electrode material has \theta_{0\%}^{\rm pos}=0.99 θ 0 % p o s ​ = 0 . 9 9 and \theta_{100\%}^{\rm pos}=0.49 θ 1 0 0 % p o s ​ = 0 . 4 9 . If \theta_k^{\rm pos}=0.59 θ k p o s ​ = 0 . 5 9 , what is the present cell state-of-charge (in percent)? Round to the nearest percent. 1 point 4 . Question 4 Suppose that a lithium-ion cell having total charge capacity Q=10 Q =...
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Introduction to battery-management systems- COURSERA WEEK 03 QUIZ -1.3.4 ANSWERS

 Introduction to battery-management systems- COURSERA WEEK 03 QUIZ -1.3.4 ANSWERS


Question 1

Consider the voltage-divider circuit:

What is the voltage v (in V)?

1 / 1 point
4
Correct

Yes. By the voltage-divider equation on slide 4 of this lesson, v = 4 / (1 + 4) \times 5.

Question 2

Consider the voltage-divider circuit:

What is the value of the resistance R (in k\Omega)?

1 / 1 point
200
Correct

Yes. By the voltage-divider equation on slide 5 of this lesson, R = 2 / (5 - 2) \times 300.

Question 3

Consider an NTC thermistor having R_0 = 100k\Omega, T_0 = 25^\circC, and \beta=4282 connected in a voltage divider circuit with R_1=100k\Omega and v=5V. If we measure v_{therm}=1.5V, what is the temperature of the thermistor (in ^\circC)? Round your answer to the nearest ^\circC.

(Remember that the inverse operation to the "exp" function is the natural logarithm "ln" and not the base-10 logarithm "log".)

1 / 1 point
44
Correct

Yes. Nicely done! That is the correct temperature.


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